- #1
ritwik06
- 580
- 0
Homework Statement
If [tex]m^{2}+m' ^{2}+2mm' cos \theta=1[/tex]
[tex]n^{2}+n' ^{2}+2nn' cos \theta=1[/tex]
[tex]mn+m'n'+(mn'+m'n)cos \theta =0[/tex],
then prove that [tex]m^{2}+n^{2}=cosec^{2} \theta[/tex]
The Attempt at a Solution
I have tri a lot but its difficult to eliminate m' or n'
If I add the first to equations and separate m^2+n^2 to left ide, again its difficult to prov the RHS to [tex]cosec ^{2} \theta[/tex]