- #1
sammyj
- 4
- 0
What is the instantaneous velocity of a freely falling object 10 s after it is released from a position of rest? What is its average velocity during this 10 s interval? How far will it fall during this time?
I had asked a few friends for help and I keep getting mixed answers.
v = gt
98m/s = 9.8m/s * 10
Average V = initial v + final v
2
Average V = 0m/s + 98m/s
2
Average V=49m/s
Distance Traveled d = ½ gt squared
½ * 9.8m/s * 10 squared = 490m
or
Vf=Vo+at = 0msec+10msec2(10sec)= 100msec
AverageVelocity=Vf+Vo2=100ms+0ms2=50msec
X=Vot +12at2=0ms(10sec)+12(10msec2)(10sec)2=500 meters
Who's on the right path?
I had asked a few friends for help and I keep getting mixed answers.
v = gt
98m/s = 9.8m/s * 10
Average V = initial v + final v
2
Average V = 0m/s + 98m/s
2
Average V=49m/s
Distance Traveled d = ½ gt squared
½ * 9.8m/s * 10 squared = 490m
or
Vf=Vo+at = 0msec+10msec2(10sec)= 100msec
AverageVelocity=Vf+Vo2=100ms+0ms2=50msec
X=Vot +12at2=0ms(10sec)+12(10msec2)(10sec)2=500 meters
Who's on the right path?