- #1
KataKoniK
- 1,347
- 0
|x^2 - 2x - 3| = -(x^2 - 2x - 3), 0 <= x < 3
x^2 - 2x - 3, 3 <= x <=4
how did they get the intervals:
3 <= x <=4 and 0 <= x < 3?
I cannot, for the love of God, know how they determined it.
x^2 - 2x - 3, 3 <= x <=4
how did they get the intervals:
3 <= x <=4 and 0 <= x < 3?
I cannot, for the love of God, know how they determined it.