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synthetic.
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Is it always true that if; [tex] f(x) = f '(x)[/tex], then; [tex]-f (x) = - \int f '(x) [/tex] ?
That is, the negative of a derivative has an integral which is simply the negative of the original function? (ignoring arbitiary constants)
That is, the negative of a derivative has an integral which is simply the negative of the original function? (ignoring arbitiary constants)
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