- #1
BlackMamba
- 187
- 0
I have a problem which asks me to find the derivative using Part 1 of the Fundamental Theorem of Calculus.
So I know that the FTC says that if:
[itex]g(x) = \int_{a}^{h(x)} f(t) dt[/itex] then, [itex]g'(x) = f(h(x)) * h'(x)[/itex]
I've got what appears to be an easy problem, maybe too easy and because of that I think I'm doing something wrong. Below is the problem and my solution. If someone could just varify if I did it correctly or not, I would greatly appreciate it.
PROBLEM: [itex]G(x) = \int_{y}^{2} sin(x^2) dx[/itex]
My Solution:
[itex]G'(x) = sin(2^2) * 0[/itex]
[itex] = sin(4) * 0[/itex]
[itex]= 0[/itex]
Thanks for taking a look.
So I know that the FTC says that if:
[itex]g(x) = \int_{a}^{h(x)} f(t) dt[/itex] then, [itex]g'(x) = f(h(x)) * h'(x)[/itex]
I've got what appears to be an easy problem, maybe too easy and because of that I think I'm doing something wrong. Below is the problem and my solution. If someone could just varify if I did it correctly or not, I would greatly appreciate it.
PROBLEM: [itex]G(x) = \int_{y}^{2} sin(x^2) dx[/itex]
My Solution:
[itex]G'(x) = sin(2^2) * 0[/itex]
[itex] = sin(4) * 0[/itex]
[itex]= 0[/itex]
Thanks for taking a look.