- #1
hanson
- 319
- 0
Hi all!
how would you do this partial fraction problem?
[tex]\frac{1}{s(s+1)^3(s+2)}[/tex]
The answer is [tex]\frac{1}{2s}+\frac{1}{2(s+2)}-\frac{1}{s+1}-\frac{1}{(s+1)^3} [/tex]
I know that it can be done by letting
[tex] \frac{1}{s(s+1)^3(s+2)} = \frac{A}{s}+\frac{B}{s+2}+\frac{C}{s+1}+\frac{D}{(s+1)^2}+\frac{E}{(s+1)^3} [/tex] and solve for A,B,C,D and E. I tried and it is very tedious. It is easy to find A, B and E but not for the others.
Can anyone tell me a quicker way to do this? Thanks
how would you do this partial fraction problem?
[tex]\frac{1}{s(s+1)^3(s+2)}[/tex]
The answer is [tex]\frac{1}{2s}+\frac{1}{2(s+2)}-\frac{1}{s+1}-\frac{1}{(s+1)^3} [/tex]
I know that it can be done by letting
[tex] \frac{1}{s(s+1)^3(s+2)} = \frac{A}{s}+\frac{B}{s+2}+\frac{C}{s+1}+\frac{D}{(s+1)^2}+\frac{E}{(s+1)^3} [/tex] and solve for A,B,C,D and E. I tried and it is very tedious. It is easy to find A, B and E but not for the others.
Can anyone tell me a quicker way to do this? Thanks