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[tex]ty''-(t+1)y'+y=t^2[/tex]
I know I have to use variation of parameters to solve this.
But I am stuck and cannot figure out how to get the homologous equation!
[tex]y''-(1+\frac{1}{t})y'+\frac{1}{t}*y=t[/tex]
I don't know how to solve this homologous equation in this format.
Is it R^2+(1+1/t)R+1/t = 0 ?
How would I get my two solutions from this?
Thanks!
I know I have to use variation of parameters to solve this.
But I am stuck and cannot figure out how to get the homologous equation!
[tex]y''-(1+\frac{1}{t})y'+\frac{1}{t}*y=t[/tex]
I don't know how to solve this homologous equation in this format.
Is it R^2+(1+1/t)R+1/t = 0 ?
How would I get my two solutions from this?
Thanks!
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