Understanding Light: Electric & Magnetic Propagation

  • Thread starter Wittyname6
  • Start date
  • Tags
    Light
In summary, there is a relationship between changing electric and magnetic fields, as a changing electric field creates a magnetic field and vice versa. This is represented by the sinusoidal electric and magnetic waves traveling in the same direction, with the electric wave perpendicular to the magnetic wave. The axes in the graph represent time, space, and the strength of the field, with the fields being vectors. The amplitude of the wave represents the strength of the field, and a shorter wavelength does not necessarily mean more bounces off atoms. Moving a bunch of charges creates a magnetic field, but at macroscopic distances, the fields from positive and negative charges cancel out. At atomic-level distances, there may be small magnetic effects.
  • #1
Wittyname6
19
0
I've heard that a changing electric field creates a magnetic field and a changing magnetic field creates an electric field, but I am still very confused about exactly how this propagation actually works.

The visual representation of an electromagnetic wave I have seen are a sinusoidal electric and magnetic field waves traveling in the same direction, but a line connecting the electric waves peak and trough would lie perpendicular to the magnetic fields peak and trough. These lines would also lie perpedicular to the direction the wave is travelling. It looks like this:
http://ffden2.phys.uaf.edu/webproj/212_spring_2014/Amanda_Mcpherson/Amanda_McPherson/em_electric_magnetic_propagating_waves.jpg

At this point I am already confused. To my knowledge, an electric field exists at all points in space with different intensities. It is a scalar quantity. How then, can this field be 'waving' in a sinusoidal pattern through space?
 
Last edited by a moderator:
Science news on Phys.org
  • #2
Wittyname6 said:
To my knowledge, an electric field exists at all points in space with different intensities. It is a scalar quantity.

http://en.wikipedia.org/wiki/Electric_field#Electric_Field
the E field can be thought of as a function that associates a vector with every point in space.
 
  • #3
Yes, you are right, electric field is a vector. I spoke mistakenly.

However, in the graph, the direction is taken into account by the wave being above or below the axis, I believe. What I meant to communicate was that the strength of the field is a scalar quantity.

Perhaps the crux of the problem lies with the fact that I don't understand what the axes represent. The black axis seems to be the line of propagation. It represents time, and since the velocity is constant, space.
The red and blue axes I am baffled by. My best guess is that it represents the strength of the field. But it must represent the strength of the field at some point in space (This is what I called a scalar quantity, I was thinking of it as a point in space with a certain strength). I would guess that this point is on the black axis.

So we have a point on the black axis. We can know the strength of the electric and magnetic fields at this point by looking at the graph and seeing how high the wave is at this point. This would all make sense to me, except that it says that the E-field and M-field have to be perpendicular to each other. If the height of the wave only expresses the strength of the field, a scalar quantity, then it cannot be perpendicular to another scalar quantity.
 
  • #4
Wittyname6 said:
Yes, you are right, electric field is a vector. I spoke mistakenly.
...
If the height of the wave only expresses the strength of the field, a scalar quantity, then it cannot be perpendicular to another scalar quantity.
The field is a vector. It can be perpendicular to other vectors. I don't get why you seem to recognize that it is a vecor and then object to it being perpendicular to another vector. The fields simply are not scalars, they are vectors.

I couldn't see the link in your OP, but usually the drawings illustrate the vector fields evaluated along a line in space at a single instant in time.
 
Last edited:
  • #5
I'll try another link: https://encrypted-tbn0.gstatic.com/...ODenuFlyiFPOf7sZGLBFvtNKaNfz2JqzKMVboSx3Iq076

In this picture there are black, blue, and yellow axes. So I'll use that terminology. I was saying that the *strength* of the field is a scalar. I'm interpreting the amplitude of the wave as the strength of the field, where being on the other side of the axis is like making the number negative. If the amplitude is the strength of the field, and the strength is scalar, then the amplitude is a graphical representation of a scalar quantity, and scalars cannot be perpendicular.
 
  • #6
Let me ask you this: given that the fields are vectors and that those vectors are perpendicular, how would you draw it?
 
  • Like
Likes 1 person
  • #7
Did you receive my personal message?
 
  • #8
I'm not sure how I would draw it because I am not certain of what I am drawing.

Edit: That's not a very clear thing to say, sorry. I think I am beginning to understand now. Give me a moment to think about it.
 
Last edited:
  • #9
I think I understand now. Your question about how I would draw it really helped. Thanks!

I have a bunch more questions, if you're still willing to help.

When I look up why the sky is blue, I'm told the reason is blue light has a shorter wavelength, so it bounces into atoms in the sky more often. My new understanding of light is that it is essentially 1-dimensional. A shorter wavelength means that the distance between the peaks of the fields is less. So how would a shorter wavelength make it bounce off of atoms more often?

When I lift my arm, aren't I creating a magnetic field? I'm moving a bunch of charges.

In a material like a pencil, there are a bunch of atoms with electrons orbiting protons and neutrons. Don't they create a magnetic field, why can't I detect it.

If light is a magnetic and electric field, shouldn't I be able to shine a flashlight on a magnet and get it to move or react or something?

I still have questions about how light actually propagates, but I'll start a new thread for that.
 
  • #10
Wittyname6 said:
When I lift my arm, aren't I creating a magnetic field? I'm moving a bunch of charges.

In a material like a pencil, there are a bunch of atoms with electrons orbiting protons and neutrons. Don't they create a magnetic field, why can't I detect it.

Your arm and the pencil have equal amounts of positive and negative charges in close proximity. They generate magnetic fields which are equal in magnitude and opposite in direction, and therefore add up to zero, at least at macroscopic and even ordinary microscopic distances. If you get down to atomic-level distances, in among the atoms, there are probably small magnetic effects at that scale.
 
  • #11
Ok, so I understand about the situation when I lift my arm, but not about a stationary pencil. In the pencil, there are effectively a bunch of protons, which are not moving, and a bunch of electrons which are moving very rapidly. Since the electrons are the only ones moving, they create a magnetic field, and the protons magnetic field can't cancel out.
 
  • #12
Wittyname6 said:
Ok, so I understand about the situation when I lift my arm, but not about a stationary pencil. In the pencil, there are effectively a bunch of protons, which are not moving, and a bunch of electrons which are moving very rapidly. Since the electrons are the only ones moving, they create a magnetic field, and the protons magnetic field can't cancel out.

Which way are the electrons moving?
 
  • #13
They are moving in orbit around a proton.
 
  • #14
Wittyname6 said:
I'm not sure how I would draw it because I am not certain of what I am drawing.

Edit: That's not a very clear thing to say, sorry. I think I am beginning to understand now. Give me a moment to think about it.
No worries, it takes time. For clarity, what you are trying to draw is two fields throughout all space and time, each of the form ##\mathbf{A}\cos(kx-\omega t)##, where the respective A vectors are mutually orthogonal. It is not easy to draw, so it can be confusing.
 
  • #15
Wittyname6 said:
They are moving in orbit around a proton.

All of them? Moving? Around one proton? In the same direction? You know the Bohr model is wrong, right?
 
  • #16
Sorry I misspoke. If we take a hydrogen atom, we have a stationary proton in the center, and then its electron is moving about on the outside somehow. So the electron is moving and the proton is not. The electron would create a magnetic field and the proton would not. So there would be a net field. If this is happening in a bunch of atoms all packed together, couldn't that field be strengthened to some noticeable level?

In the equation Acos(kx-wt) what do k, x, w, and t stand for?
 

1. What is light?

Light is a form of electromagnetic radiation that can be perceived by the human eye. It is composed of electric and magnetic fields that oscillate at right angles to each other and travel through space at the speed of light.

2. How does light propagate?

Light propagates through the emission of photons, which are particles that carry energy. These photons are created when an electric charge moves, such as in the atoms of a light source. As the photons travel, they create oscillating electric and magnetic fields that are perpendicular to the direction of propagation.

3. What is the electromagnetic spectrum?

The electromagnetic spectrum is the range of all possible frequencies of electromagnetic radiation. It includes all forms of light, from radio waves with long wavelengths to gamma rays with short wavelengths. Visible light, which is the type of light that can be seen by the human eye, is just a small portion of the electromagnetic spectrum.

4. How does light interact with matter?

Light can interact with matter in various ways, depending on the properties of the matter and the wavelength of the light. Some of these interactions include absorption, reflection, scattering, and refraction. These interactions determine how light is perceived by our eyes and how it is used in various scientific fields.

5. What are some applications of understanding light propagation?

Understanding light propagation has many practical applications, including in technologies such as fiber optics, lasers, and solar cells. It is also important in fields such as astronomy, where it helps us to observe and study objects in the universe. Additionally, understanding light can also contribute to the development of new materials and medical treatments.

Similar threads

Replies
6
Views
13K
Replies
4
Views
1K
Replies
18
Views
14K
Replies
41
Views
3K
  • Introductory Physics Homework Help
Replies
2
Views
353
Replies
4
Views
2K
  • Electromagnetism
Replies
2
Views
395
Replies
2
Views
11K
  • Special and General Relativity
Replies
17
Views
680
  • Introductory Physics Homework Help
Replies
10
Views
1K
Back
Top