- #1
NasuSama
- 326
- 3
Homework Statement
Liquid 1 (density [itex]ρ_{1}[/itex] = 8290 kg/m³) is poured into a large open cylinder to a depth of [itex]d_{1}[/itex] = 85.9 cm. Liquid 2 (density [itex]ρ_{2}[/itex] = 5695 kg/m³) is then poured on top of liquid 1 to a depth of [itex]d_{2}[/itex] = 70.3 cm. Then liquid 3 (density [itex]ρ_{3}[/itex] = 2933 kg/m³) is poured on top of liquid 2 to a depth of [itex]d_{3}[/itex] = 66.9 cm. Assume the liquids are immiscible (do not mix at all), so the total depth of the fluid is [itex]d_{TOT}[/itex] = 223.1 cm. Find P, the pressure at the bottom of the flask.
Homework Equations
I would assume that it's this formula, the Pascal's principle...
[itex]\Delta P = \rho g(\Delta h)[/itex]
The Attempt at a Solution
I combined all the values altogether to obtain the pressure, but it's incorrect. I've heard that someone said that the pressure at the bottom will be lower after adding the liquids on top. I am not sure how to show this. I can only think that Pascal's principle is the only formula to start.