- #1
predentalgirl1
- 67
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1. A horizontal magnetic field of 1.0 x 10^-4 T is at an angle of 30 degrees to the direction of the current in a straight, horizontal wire 75 cm long. If the wire carries a current of 15 A, what is the magnitude of the force on the wire?
2.B be the magnetic field = 1.0 x 10-4 T
Θ be the angle between the magnetic field and current = 300
L be the length of the wire = 75 cm = 0.75m
I be the current in the wire = 15 A
F be the force in the wire ?
From basic magnetic force
F = qvB sin Θ
F = q(L/t)B sin Θ
F = (q/t)LB sin Θ
F = I L B sin Θ
3. F = 15 x 0.75 x 1.0x10-4 sin 300
F = 11.25 x 10-4 sin 300
F = 11.25 x 10-4 (1/2)
F = 5.625 10-4 N
F = 0.5625mN
(Ans)
2.B be the magnetic field = 1.0 x 10-4 T
Θ be the angle between the magnetic field and current = 300
L be the length of the wire = 75 cm = 0.75m
I be the current in the wire = 15 A
F be the force in the wire ?
From basic magnetic force
F = qvB sin Θ
F = q(L/t)B sin Θ
F = (q/t)LB sin Θ
F = I L B sin Θ
3. F = 15 x 0.75 x 1.0x10-4 sin 300
F = 11.25 x 10-4 sin 300
F = 11.25 x 10-4 (1/2)
F = 5.625 10-4 N
F = 0.5625mN
(Ans)