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philadelphia
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1. A 1.0 kg mass moving with a velocity v m/s strikes a stationary mass (assume no frictional losses).
a. Is it possible for both masses to move in the same direction and at the same speed after the collision? If so, find the value of the stationary mass.
b. Is it possible for both masses to move in OPPOSITE directions but with the same speed after the collision? If so, find the value of the stationary msss.
m1v1=m2v2
Not sure if this is the right path for (a)
m1 = 1kg
v2 = 0 m/s
a. after collision
v1 = v2 = v = 5(random variable to plug)
(1kg)(5m/s) = m2(5m/s)
b. i don't get help help me with a step
2. A space probe of mass 100kg is traveling due East at 5000m/s. It fires a thruster for 7 minutes to change direction. If the engine produces 500 Newtons of force in a direction 45 degrees North of West.
a)Find the impulse
b)FinD the new momentum vector of the spacecraft
c)Find the new speed of the spacecraft and its direction
d) If the fuel is ejected at 3000m/s find the mass of the propellant used in the burn
F[tex]\Delta[/tex]t = m[tex]\Delta[/tex]V
m= 100 kg
v=5000 m/s
t= 7min = 420 secs
500N 45 degrees NoW
a) m[tex]\Delta[/tex]V = 100kg(5000m/s) = 500000 kg m/s
b) I am stuck afterwards I am guessing its cos(45)500N * 420 seconds
c) answer from b divide by 100kg (F[tex]\Delta[/tex]t / m = V)
d) I don't know
a. Is it possible for both masses to move in the same direction and at the same speed after the collision? If so, find the value of the stationary mass.
b. Is it possible for both masses to move in OPPOSITE directions but with the same speed after the collision? If so, find the value of the stationary msss.
Homework Equations
m1v1=m2v2
The Attempt at a Solution
Not sure if this is the right path for (a)
m1 = 1kg
v2 = 0 m/s
a. after collision
v1 = v2 = v = 5(random variable to plug)
(1kg)(5m/s) = m2(5m/s)
b. i don't get help help me with a step
2. A space probe of mass 100kg is traveling due East at 5000m/s. It fires a thruster for 7 minutes to change direction. If the engine produces 500 Newtons of force in a direction 45 degrees North of West.
a)Find the impulse
b)FinD the new momentum vector of the spacecraft
c)Find the new speed of the spacecraft and its direction
d) If the fuel is ejected at 3000m/s find the mass of the propellant used in the burn
Homework Equations
F[tex]\Delta[/tex]t = m[tex]\Delta[/tex]V
m= 100 kg
v=5000 m/s
t= 7min = 420 secs
500N 45 degrees NoW
The Attempt at a Solution
a) m[tex]\Delta[/tex]V = 100kg(5000m/s) = 500000 kg m/s
b) I am stuck afterwards I am guessing its cos(45)500N * 420 seconds
c) answer from b divide by 100kg (F[tex]\Delta[/tex]t / m = V)
d) I don't know