- #1
iluvphys
- 27
- 0
Hi friends,
I am preparing for my exam and i am stuck with this problem, please help me out.
It won't take too long, I hope.
Two bodies A and B have masses mA and mB respectively and collide completely inelastic.
Given that the mass of body A is 1200 kg and body B is 800 kg determine the avergage force vectors acting on each body during the collision. The collision itself lasts for 0.2 s.
Velocity of body A: (5i + 3j) m/s
Velocity of body B: (-i + 4j) m/s
Common velocity after collision I found to be: (2.6i + 3.4j) m/s (this eq was derived in a previous question with mA = 3/2 mB)
Well, I have tried using the momentum impulse theorem only to find out that the total momentum was conserved, which is good indeed. However I don't know how to find the answer I have kind of like used up my knowledge on impulse.
The answer is (-14400i + 2400j) N.
I have no clue how this answer was derived.
Please help.
I am preparing for my exam and i am stuck with this problem, please help me out.
It won't take too long, I hope.
Homework Statement
Two bodies A and B have masses mA and mB respectively and collide completely inelastic.
Given that the mass of body A is 1200 kg and body B is 800 kg determine the avergage force vectors acting on each body during the collision. The collision itself lasts for 0.2 s.
Homework Equations
Velocity of body A: (5i + 3j) m/s
Velocity of body B: (-i + 4j) m/s
Common velocity after collision I found to be: (2.6i + 3.4j) m/s (this eq was derived in a previous question with mA = 3/2 mB)
The Attempt at a Solution
Well, I have tried using the momentum impulse theorem only to find out that the total momentum was conserved, which is good indeed. However I don't know how to find the answer I have kind of like used up my knowledge on impulse.
The answer is (-14400i + 2400j) N.
I have no clue how this answer was derived.
Please help.