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Cu - 1s2 2s2 2p6 3s2 3p6 4s1 3d10
Cu2+ - 1s2 2s2 2p6 3s2 3p6 4s0 3d7
This is the configuration of the respective atoms and ions..
According to Aufbau's principle.The subshells with lesser energies get filled first !
Which means 4s sub shell is filled and only after that 3d10 sub shell is filled because the energy of 3d subshell is be greater than 4s subshell ie.4s < 3d energy.
Now if we are removing electrons and converting Cu to Cu2+ it means that energy should be provided to remove the electrons,If that is the case then.
Since, 3d subshell has more energy than 4s orbital,therefore less energy will be required for removing electrons from 3dorbital because they already have greater energy than 4s orbital..
But 4s electrons are removed while ionizing ..How ?
I hope you understood my question...Please giveme a rpoper reason for this..
Thanks,
-5416339
Cu2+ - 1s2 2s2 2p6 3s2 3p6 4s0 3d7
This is the configuration of the respective atoms and ions..
According to Aufbau's principle.The subshells with lesser energies get filled first !
Which means 4s sub shell is filled and only after that 3d10 sub shell is filled because the energy of 3d subshell is be greater than 4s subshell ie.4s < 3d energy.
Now if we are removing electrons and converting Cu to Cu2+ it means that energy should be provided to remove the electrons,If that is the case then.
Since, 3d subshell has more energy than 4s orbital,therefore less energy will be required for removing electrons from 3dorbital because they already have greater energy than 4s orbital..
But 4s electrons are removed while ionizing ..How ?
I hope you understood my question...Please giveme a rpoper reason for this..
Thanks,
-5416339