Integral Form of the Momentum Equation - Reducer Question

In summary, the problem involves determining the total force required to support a reducer with an internal volume of 0.2m^3 and a mass of 25 kg, while pumping oil with a specific gravity of 0.72. The given parameters include the diameter of the reducer (d1 = 0.4m), the diameter of the smaller pipeline (d2 = 0.2m), the velocity of the oil (u1 = 3m/s), and the pressures at the inlet and outlet (p1 = 58.7 kPa, p2 = 49kPa gauge). Using the equations for fluid flow and momentum, the resulting force is F = −3.4xˆ +1
  • #1
MrWinesy
9
0

Homework Statement



The internal volume of the reducer is 0.2m^3 and its mass is 25 kg. The fluid being pumped is oil (specific gravity of 0.72).
Evaluate the total force that must be provided to support the reducer.

d1 = 0.4m
d2 = 0.2m
u1 = 3m/s
p1 = 58.7 kPa
p2 = 49kPa (gauge)


Homework Equations




Qin=Qout

mdot=ρ*A*u

A=(∏*d^2)/4


The Attempt at a Solution



Tried. Failed. Help.
 
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  • #2
the answer is apparently F = −3.4xˆ +1.66yˆ kN but I am in need of the working please.
 
  • #3
What does a 'reducer" do?
 
  • #4
A reducer couples a larger diameter pipeline to a smaller diameter pipeline, hence the two diameters specified in the OP.
 
  • #5
SteamKing said:
A reducer couples a larger diameter pipeline to a smaller diameter pipeline, hence the two diameters specified in the OP.

Thanks SK!

But - what is meant by its volume? Is it a tapered section of pipe going from the larger to the smaller diameter?
 
  • #6
It can be. More often it is a cast fitting, either flanged or suited to welding, with a curved transition between the larger and smaller diameters, so that the overall length of the fitting is kept small. The volume, I believe, is just what it implies, the volume of the internal space of the reducer.
 
  • #7
SteamKing said:
It can be. More often it is a cast fitting, either flanged or suited to welding, with a curved transition between the larger and smaller diameters, so that the overall length of the fitting is kept small. The volume, I believe, is just what it implies, the volume of the internal space of the reducer.

yea this is right. it can be basically thought of as a converging pipe and the question is based on the internal volume as this helpful fella said. and the mass is the mass of the actual reducer.

i have obtained the answer but not confident on my methods. anyone else had any luck?
 
  • #8
Thanks to my friend Chestermiller from a similar previous problem, the approach here is to consider the change in momentum per unit time of the oil and equate that to the (longitudinal) force exerted on the reducer.
 

1. What is the integral form of the momentum equation?

The integral form of the momentum equation is a mathematical representation of Newton's second law of motion, which states that the net force acting on an object is equal to its mass times its acceleration. In its integral form, the equation takes into account the change in momentum over a given interval of time.

2. How is the integral form of the momentum equation different from the differential form?

The differential form of the momentum equation is based on the instantaneous forces and velocities acting on an object, while the integral form takes into account the change in momentum over a given interval of time. In other words, the integral form considers the cumulative effect of forces over time, while the differential form looks at the instantaneous values.

3. What is the significance of the integral form in fluid mechanics?

The integral form of the momentum equation is particularly useful in fluid mechanics because it allows for the analysis of forces acting on a fluid element as it moves through a system. This is important in understanding how fluids behave and how they interact with their surroundings.

4. How is the integral form of the momentum equation applied in real-world situations?

The integral form of the momentum equation is used in a variety of engineering and scientific applications, such as analyzing the forces on aircrafts, studying the flow of fluids through pipes, and designing hydraulic systems. It is also commonly used in computational fluid dynamics simulations.

5. Can the integral form of the momentum equation be simplified for certain cases?

Yes, the integral form of the momentum equation can be simplified for certain cases, such as when the fluid is at rest or when it is flowing in a steady state. In these cases, some terms in the equation may cancel out, making the calculations easier. However, for more complex and dynamic systems, the full integral form must be used to accurately analyze the forces at play.

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