How do I derive the projectile parabola equation using equations of motion?

[nameVoid]

write out the six equations of motion in 1 dimension for constant acceleration and from those derive the equation y(x) for the parabolic path of a projectile.


I have
v2=v1+at
x2=x1+1/2 (v1+v2)t
x2=x1+v1t+1/2 at^2
v2^2=v1^2+2a(x2-x1)

not sure of the remaining 2 and the derivation

 

[Danger]

42
:uhh:

 

[tiny-tim]

hi nameVoid!

(try using the X² and X₂ icons just above the Reply box )

I have
v2=v1+at
x2=x1+1/2 (v1+v2)t
x2=x1+v1t+1/2 at^2
v2^2=v1^2+2a(x2-x1)

not sure of the remaining 2 and the derivation

hmm … i have no idea what the other 2 https://www.physicsforums.com/library.php?do=view_item&itemid=204" equations are supposed to be

but anyway you should be able to get the projectile parabola by using those four …

with a = -g in the y direction, and a = 0 in the x direction