- #1
JerzeyDevil
- 2
- 0
Hi, I'm a meteorology major and my professor assumes we know how to do differential equations, and I did at one time, but I have seem to forgotten most of what to do in the past few years. I was just wondering if anyone could help me how to solve this problem...she gave us the answer and the starting point but I can't seem to get the answer she gave:
[tex]\epsilon[/tex][tex]d^{2}[/tex][tex]\Psi[/tex]/dx[tex]^{2}[/tex] + d[tex]\Psi[/tex]/dx = -1
Boundary conditions:
[tex]\Psi[/tex] = 0
[tex]\Psi[/tex] = 0
[tex]\epsilon[/tex] = constant
It may be a bit hard to see in text but its psi(x=0) = psi(x=1) = 0 as the boundary condtions.
Any help would be appreciated!
[tex]\epsilon[/tex][tex]d^{2}[/tex][tex]\Psi[/tex]/dx[tex]^{2}[/tex] + d[tex]\Psi[/tex]/dx = -1
Boundary conditions:
[tex]\Psi[/tex] = 0
[tex]\Psi[/tex] = 0
[tex]\epsilon[/tex] = constant
It may be a bit hard to see in text but its psi(x=0) = psi(x=1) = 0 as the boundary condtions.
Any help would be appreciated!