- #1
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Homework Statement
Determine the threshold energy for electrons to produce Cerenkov radiation in glass (refractive index n=1.52).
The Attempt at a Solution
The only equations given in my notes are:
cos [itex]\theta[/itex][itex]_{C}[/itex]=1/[itex]\beta[/itex]n for [itex]\beta[/itex]>1/n
and
dN/d[itex]\lambda[/itex]=[itex]\frac{2\pi\alpha}{\lambda^{2}}[/itex]L sin[itex]^{2}[/itex] [itex]\theta[/itex][itex]_{C}[/itex]
How the second equation relates to the energy, I don't know. What does dN/d[itex]\lambda[/itex] have to do with the energy? And how is the 'threshold' supposed to be worked out?
Is E=mc[itex]^{2}[/itex] in this case? Is the energy supposed to be deduced from [itex]\lambda[/itex]?
Please help.
My textbooks and the internet don't tell me know to do this sort of question either.