- #1
jstep
- 11
- 0
Is there a way to simplify a^logn, a = 1 / b
I don't know if this is possible, but I thought I would ask for another opinion if I'm overlooking something. Anyway, is there a way to simplify alogbn, a = 1 / b
I don't know if this is possible, but I thought I would ask for another opinion if I'm overlooking something. Anyway, is there a way to simplify alogbn, a = 1 / b