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Homework Statement
A hanging weight with a mass of 25kg is suspended from a rope from a wall. The rope with the weight is wrapped around a pully which is also attached to a different wall. The angle that rope a(rope with mass) makes with the wall is 41 degrees, and the angle of the other rope with the other wall is 69.5 degrees. Find the force of tension in each rope.
Homework Equations
EFx=0
Efy=o
The Attempt at a Solution
EFx=0
Acos(49)-Bcos(20.5)=0
A=Bcos(20.5)/cos(49)
EFy=0
Asin(49)+Bsin(20.5)=mg
(Bcos(20.5)/cos(49))sin(49)+Bsin(20.5)=mg
B=172N
Substitute B back into A
A=172cos(20.5)/cos(49)
A=246
I got the force of tension in A to be 246N and the tension in B to be 172N. Is this correct or am I making this to easy? Also is it just a conicedence that the tension on the rope with the weight is the force of gravity?
Thanks for your help.
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