- #1
DrAlloway
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Will this wire burn me or melt my clothes ??
I am making a heated motorcycle jacket - so 13 volts DC (actual measurement while riding).
For heating wire I am using 30 gauge (7 strand x 40 AWG) tinned copper wire with Teflon insulation (good to 250C) which has a resistance of 0.102 ohms per foot (actual measurement as versus 0.103 from tables).
I will sew 22 feet of this wire into my jacket so that gives me:
2.24 ohms, 5.8 amps, and 75 watts.
75 watts over 22 feet is 3.43 watts per foot.
The practical question is will this wire burn me or melt my polyester jacket ??
I do Not need the exact temperature of this wire. There are no second or third degree issues as the wire is sewn into polyester insulation between my jacket shell and liner. So there is NO air circulation, fan, or any complications.
There must be a formula for calculating the APPROXIMATE temperature of this wire.
Any help will be greatly appreciated as I am definitely not an electrical engineer.
thanks, Bob
I am making a heated motorcycle jacket - so 13 volts DC (actual measurement while riding).
For heating wire I am using 30 gauge (7 strand x 40 AWG) tinned copper wire with Teflon insulation (good to 250C) which has a resistance of 0.102 ohms per foot (actual measurement as versus 0.103 from tables).
I will sew 22 feet of this wire into my jacket so that gives me:
2.24 ohms, 5.8 amps, and 75 watts.
75 watts over 22 feet is 3.43 watts per foot.
The practical question is will this wire burn me or melt my polyester jacket ??
I do Not need the exact temperature of this wire. There are no second or third degree issues as the wire is sewn into polyester insulation between my jacket shell and liner. So there is NO air circulation, fan, or any complications.
There must be a formula for calculating the APPROXIMATE temperature of this wire.
Any help will be greatly appreciated as I am definitely not an electrical engineer.
thanks, Bob