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Homework Statement
L[f(t)]= 1/(s^2+1)^2 + 1/(s^2+1)
L[f(t)]= ln(s+a) where 'a' is a constant
Homework Equations
The Attempt at a Solution
I know that the inverse laplace of 1/(s^2+1) is sin(t), but how do I deal with the squared form of it.
I have never encountered a logarithmic funcion for laplace, so can it be inverted back to f(t) with some of the common solution of conversion?
Thanks