- #1
stepan
- 10
- 0
Hello everyone. I am currently a grade 11 High-School student and have embarked on making the Waterphone() for my musical instrument project. Fortunately, I have stumbled upon this how-to for something to start on http://www.em411.com/show/blog/7895/0/DIY_Waterphone.html . I will make it look more like this however: http://www.fundomentalmusic.com/_Media/dscn0569.jpg
Although I have a general idea of how to get the frequencies, I am still unsure and need a second consultation (My teacher said she didn't know unless she did research, and I don't think she will be using her time for that :P ).
For the Rods
I will use the table from http://www.phy.mtu.edu/~suits/notefreqs.html to get frequencies of different notes.
I will use the same rods, so the only determinate for frequency will be height.
Because the rods are closed-air columns, I know the height of the rod will be 1/4*wavelength
Therefore for C4
[tex]\int[/tex]=261.63Hz
v=345m/s(at 22 degrees Celcius)
[tex]\int[/tex]=v[tex]\lambda[/tex]
[tex]\lambda[/tex]= 0.76m
therefore rod height is 19cm .
Is this right? . This is the only normal solution i came up with, although there is something that just doesn't sit right with me.
For the Cylinder in the center
I am not sure what that is for the waterphone. I think it is open at both ends but I don't know what note that is supposed to make, if it's supposed to make a note at all. Any help from people acquainted with the waterphone on this issue would be greatly appreciated.
If it is open at both ends though would i count the space that the cylinder is attached to and say it is a closed air-column, or say that it is an open air column and count just the rod.
Any comments would be greatly appreciated!
Stepan
Although I have a general idea of how to get the frequencies, I am still unsure and need a second consultation (My teacher said she didn't know unless she did research, and I don't think she will be using her time for that :P ).
For the Rods
I will use the table from http://www.phy.mtu.edu/~suits/notefreqs.html to get frequencies of different notes.
I will use the same rods, so the only determinate for frequency will be height.
Because the rods are closed-air columns, I know the height of the rod will be 1/4*wavelength
Therefore for C4
[tex]\int[/tex]=261.63Hz
v=345m/s(at 22 degrees Celcius)
[tex]\int[/tex]=v[tex]\lambda[/tex]
[tex]\lambda[/tex]= 0.76m
therefore rod height is 19cm .
Is this right? . This is the only normal solution i came up with, although there is something that just doesn't sit right with me.
For the Cylinder in the center
I am not sure what that is for the waterphone. I think it is open at both ends but I don't know what note that is supposed to make, if it's supposed to make a note at all. Any help from people acquainted with the waterphone on this issue would be greatly appreciated.
If it is open at both ends though would i count the space that the cylinder is attached to and say it is a closed air-column, or say that it is an open air column and count just the rod.
Any comments would be greatly appreciated!
Stepan
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