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Confusion about force 
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#1
Nov2313, 08:30 PM

P: 59

I have a confusion:
If we push an object of 10 kg with force of 60N once, does it accelerate constantly with 6m/s/s forever neglecting any resistance ? So, does this mean if this moving object collides with something the maximum force it applies is 60N? 


#2
Nov2313, 08:40 PM

P: 44

I probably shouldn't be answering stuff because I am new too. But I'll have a crack at it anyway.
P=mv where p is momentum and momentum is conserved. However you said it was only pushed once with 60N which makes me wonder if it would have a constant acceleration of 6m/s/s. I would have thought it would require a force acting on it to achieve constant acceleration. Otherwise it may have uniform motion of 6 m/s meaning 10kg multiplied by 6 which equals 60N. In that case yes it would hit something with 60N of force. But I am assuming this is a object in space with no resistance or opposing forces acting on it. 


#3
Nov2313, 10:08 PM

Sci Advisor
Thanks
P: 3,458

Repeat this calculation with something soft and squishy, so that it compresses by 10 centimeters, and you'll get a much smaller force. 


#4
Nov2413, 08:10 PM

P: 15

Confusion about force
For your first question, the answer is yes. It will constantly increase its speed but the rate of change of the speed is constant (acceleration is constant).



#5
Nov2413, 08:35 PM

P: 656




#6
Nov2413, 08:39 PM

P: 15

Yes you are right. I've just read it again. It's a bad thing from me not to read the word "once". In this case, Nugatory's answer is correct.



#7
Nov2513, 11:40 AM

P: 126

@Nugatory , isn't the force applied is 20000000 and not 12000000 because the mass is 10kg not 6 kg......!



#8
Nov2513, 12:15 PM

Sci Advisor
Thanks
P: 3,458




#9
Nov2613, 06:35 AM

PF Gold
P: 1,463

##F=\frac{mvmu}{t}## Where u=Initial velocity ,v= final velocity For example,Object was traveling at a constant velocity and has the same. It gets in contact with a wall or something,the force exerted is determined by the time taken for it to stop. 


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