- #1
sfx81
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Hi, I am trying to calculate Kinetic energy of system where a mass m(0.20 kilogram) attached at one ond of turntable rotating at 1 revolution per second. The radius of turntable is 6cm.
Here I solve it, please correct
Kinetic Energy = (1/2)mv2
calculating velocity at 1 rpm, and radius = 6cm
so for circumfrance of circle = 2*pi*r
v = 2 * 3.14 * 6cm = 37.69 cm = 0.3769 meters/second
K.E = 0.5 * 0.20 * 0.372 meters
= 0.0136 Joules <=== Is this correct ?
Any help will be appreciated.
Thanks
Here I solve it, please correct
Kinetic Energy = (1/2)mv2
calculating velocity at 1 rpm, and radius = 6cm
so for circumfrance of circle = 2*pi*r
v = 2 * 3.14 * 6cm = 37.69 cm = 0.3769 meters/second
K.E = 0.5 * 0.20 * 0.372 meters
= 0.0136 Joules <=== Is this correct ?
Any help will be appreciated.
Thanks