Momentum Conservation in Ideal Gas & Piston Collision

In summary, the momentum of the atom is not conserved in this collision, as the change in direction of the atom's velocity results in a change in momentum. However, whether momentum is conserved or not depends on how the system is defined - if the system is only the atom, then momentum is not conserved due to the external impulse from the piston, but if the system includes the piston and cylinder, then momentum is conserved due to the lack of external impulse. The test for conservation of momentum is the impulse momentum relationship, which states that the external impulse is equal to the change in momentum.
  • #1
qazxsw11111
95
0

Homework Statement


The cylinder and piston are made of a thermal insulator. An atom of a gas collides with the piston at an angle and bounces off at an angle. State with a reason whether momentum of the atom is conserved in this collision.


Homework Equations





The Attempt at a Solution


I think that momentum of atom is not conserved as it is a vector quantity and hence change in momentum when there is a change in direction of the atom velocity.

However, the answer says that it is how you consider what is the "system". If atom is the "system", momentum is changed. If "piston+cylinder+atom"=system, momentum is conserved.

Im really confused! Which one is right?
 
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  • #2
Hi qazxsw11111,

qazxsw11111 said:

Homework Statement


The cylinder and piston are made of a thermal insulator. An atom of a gas collides with the piston at an angle and bounces off at an angle. State with a reason whether momentum of the atom is conserved in this collision.


Homework Equations





The Attempt at a Solution


I think that momentum of atom is not conserved as it is a vector quantity and hence change in momentum when there is a change in direction of the atom velocity.

However, the answer says that it is how you consider what is the "system". If atom is the "system", momentum is changed. If "piston+cylinder+atom"=system, momentum is conserved.

Im really confused! Which one is right?

I'm not sure what you are asking here; you have the same answer as the answer key. The momentum of the atom changes.

If you are examining just the atom by itself (which is what is meant by defining the system to be the atom), then during the collision there is a large external impulse on the system--from the piston. With a large external impulse, the momentum changes (is not conserved).

If your system is (piston+cylinder+atom), then there is no external impulse due to the collision, because the collision forces are between system objects (and so action-reaction forces will have cancelling impulses). So for that system momentum is conserved.

Remember that the test for conservation of momentum is the impulse momentum relationship, which for average forces is:

[tex]
\vec F_{\rm ext}\Delta t=\Delta \vec p
[/tex]

(and there is also the integral form if your problem requires it).
 
  • #3


I would say that both answers are correct. It ultimately depends on how you define the system and what external forces are acting on it.

If we consider just the atom as the system, then the momentum would not be conserved as it changes direction after colliding with the piston. However, if we consider the entire system of the piston, cylinder, and atom, then the momentum would be conserved as there are no external forces acting on the system.

Additionally, it is important to note that in an ideal gas, the collisions between gas particles and the walls of the container are elastic, meaning that there is no loss of kinetic energy in the collision. This allows for the conservation of both momentum and energy in the system.

In conclusion, both answers are valid and it is important to carefully define the system and consider external forces when analyzing the conservation of momentum in a collision.
 
Question 1: What is momentum conservation in ideal gas and piston collision?

Momentum conservation in ideal gas and piston collision refers to the principle that the total momentum of a system remains constant before and after a collision between a gas molecule and a piston. This means that the combined momentum of all the particles involved in the collision remains the same, regardless of any external forces acting on the system.

Question 2: How does momentum conservation apply to ideal gas and piston collision?

In an ideal gas and piston collision, the gas molecules are constantly colliding with the walls of the container, including the piston. These collisions transfer momentum from the molecules to the piston, causing it to move. However, according to the principle of momentum conservation, the total momentum of the system must remain constant, so the momentum transferred from the molecules to the piston must be equal to the momentum lost by the molecules during the collision.

Question 3: What factors affect momentum conservation in ideal gas and piston collision?

The main factor that affects momentum conservation in ideal gas and piston collision is the mass of the gas molecules and the piston. The larger the mass of the piston, the more momentum it will gain from the collision with the gas molecules. Other factors that can affect momentum conservation include the temperature and pressure of the gas, as well as the size and shape of the container.

Question 4: Why is momentum conservation important in ideal gas and piston collision?

Momentum conservation is important in ideal gas and piston collision because it allows us to accurately predict the motion of the gas molecules and the piston after a collision. By understanding and applying this principle, we can better understand the behavior of gases and the forces acting on them.

Question 5: How is momentum conservation different from energy conservation in ideal gas and piston collision?

Momentum conservation and energy conservation are two separate principles that apply to ideal gas and piston collision. While momentum conservation focuses on the total momentum of the system before and after a collision, energy conservation focuses on the total energy of the system. While both principles are important in understanding the behavior of gases, they serve different purposes and should not be confused with one another.

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