- #1
atrain77a
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This might be a silly one, but I'm a bit stumped:
Suppose you have a 6V battery and an unlimited supply of 1 ohm resistors.
How do you drop the potential from 6V to 4V using the resistors?
Off the top of my head I think you just put two of the resistors into a series attached to the positive side (cathode??) of the battery and you're at 4V.
However, since current isn't mentioned anywhere (think V=IR) I'm a bit confused. Is it possible to simply lower potential by stringing resistors together in series without worrying about current drawn or did I miss something simple? Thanks a bunch. -Stumped T. Day
Suppose you have a 6V battery and an unlimited supply of 1 ohm resistors.
How do you drop the potential from 6V to 4V using the resistors?
Off the top of my head I think you just put two of the resistors into a series attached to the positive side (cathode??) of the battery and you're at 4V.
However, since current isn't mentioned anywhere (think V=IR) I'm a bit confused. Is it possible to simply lower potential by stringing resistors together in series without worrying about current drawn or did I miss something simple? Thanks a bunch. -Stumped T. Day