- #1
scorpa
- 367
- 1
Hey Everyone,
I just got to my last homework question, and well I got a bit stuck.
An ion source contains two isotopes of magnesium ( 24Mg, 25Mg). These ions travels undeflected through the velocity selector (B=0.850T, [E]=4.60x10^5V/m) of a mass spectrometer. If both isotopes are singly charged, how far apart are the lines on the ion deflector? Assume magnetic field strength in the ion separator in 0.250T.
First I went v=E/B 4.60x10^5V/m / 0.850T = 5.41x10^5m/s
Then I went Bv=E to find the new electric field
(0.250T)(5.41x10^5m/s) = 1.35 x 10^5 V/m
Now I really don't know what to do, or if that was even right. I know to find the distance I need to use the equation d=V/[E] but I just can't seem to get the right answer. Apparently the answer should be 0.045m. Thanks for any help you can give.
I just got to my last homework question, and well I got a bit stuck.
An ion source contains two isotopes of magnesium ( 24Mg, 25Mg). These ions travels undeflected through the velocity selector (B=0.850T, [E]=4.60x10^5V/m) of a mass spectrometer. If both isotopes are singly charged, how far apart are the lines on the ion deflector? Assume magnetic field strength in the ion separator in 0.250T.
First I went v=E/B 4.60x10^5V/m / 0.850T = 5.41x10^5m/s
Then I went Bv=E to find the new electric field
(0.250T)(5.41x10^5m/s) = 1.35 x 10^5 V/m
Now I really don't know what to do, or if that was even right. I know to find the distance I need to use the equation d=V/[E] but I just can't seem to get the right answer. Apparently the answer should be 0.045m. Thanks for any help you can give.