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Sean1218
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Homework Statement
Two friends see each other in a store and are initially 50m apart. The first friend starts walking towards the second at a constant speed of 0.50 m/s. At the same instant, the second friend accelerates uniformly from rest at a rate of 1.0 m/s^2 toward the first friend. How long before the two friends can shake hands?
Homework Equations
v = d/t
d = vt + 1/2at^2
The Attempt at a Solution
Distance between them = 50m
Person A (on left side):
v = 0.50 m/s (is this just v or v1 or v2? not sure if i can even use the uniform acceleration equations so it's just v?)
d = vt
d = 0.50t (1)
Person B (right side):
a = -1.0 m/s^2
v1 = 0 m/s
d = 1/2(-1)t^2 (2)
(1) = (2)
0.50t = 1/2(-1)t^2
0 = -1/2t^2 - 0.50t
0 = -1/2t(t + 1)
t = 0 or t = -1
I did something wrong since t being 0 or -1 wouldn't make sense.
Not sure what else I can do or how to deal with the distance especially since they don't necessarily meet at halfway point. Any help?