- #1
delapcsoncruz
- 20
- 0
Homework Statement
Find the area between y= 1/(x2+1) and the x-axis, from x=0 to x=1
The Attempt at a Solution
so when x=0, y=1
and when x=1, y=1/2
next i plot the points, so the intersection of the given equation is (0,1) and (1,1/2)
Yh= Y-higher= 1/(x2+1)
Yl= Y-lower= 0
the strip is vertical, so the length (L) = (Yh-Yl) and the width (W) is dx
dA=LW
dA=(Yh-Yl)dx
dA=(1/(x2+1))dx
A=∫from 0-1 dx/(x2+1)
A=Arctan x from 0-1
A=Arctan 1 -Arctan 0
A=pi/4 sq.units
was my solution correct?