Doppler effect for light - how can it be explained ?

In summary, the conversation discusses the Doppler effect for light and various attempts to explain it, including analogies to sound waves and alternative theories. The summary explains that the frequency of light is related to its energy and that the Doppler effect can be understood by considering the relative motion of the light source and observer. It also mentions a link to a website that presents an alternative theory, but notes that it is not appropriate for this forum. Finally, the conversation mentions using equations and taking special relativity into account to explain the Doppler effect.
  • #1
fsoica
10
0
Did u ever try to explain Doppler effect for light in depth, at the photon level ?

I'm no scientist.

I'm trying to find a visual or mental representation of the doppler effect for electromagnetic waves.

There is no medium to vibrate. No way I can understand the phenomenon by making a parallel with sound waves, water waves or some ball throwing analogy, like in all the examples available online.

I cannot understand where does the change in frequency of the emitted light come from ? It is not supposed to be a change in photon energy also ? If so, how this loss/gain of energy occurs ?

I have a lamp. It emits green light. It starts to "run away" from me, faster and faster. According to Doppler effect theory, the light that I see becomes redder and redder, if I could say so. I find this impossible to explain.

The only webpage that contains an explanation relatively close to what I'm searching (or I think I'm searchin') is here (alternative theory website, but pls. bear with the guy, it sounds quite right):

Crackpot link deleted. Please read the rules of this site.

Is there something wrong with the above view about the phenomenon ?

Am I missing something?
Is there a possible way of popularizing the Doppler effect for light, in a different manner from the sound wave analogy ?
 
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  • #2
From the link :

"Feeling frustrated? Well that must mean that you are just inferior to me, or perhaps it’s because the whole concept is a big ball of LSD induced illogic? Let’s just not apply occam’s razor to it because I prefer being superior to you"

What a load of bull (the link). He's basically running the apparent paradox that lead to Michel-Morley's experiment, which itself lead to the need for SR.
 
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  • #3
Dr Lots-o'watts said:
From the link :

"Feeling frustrated? Well that must mean that you are just inferior to me, or perhaps it’s because the whole concept is a big ball of LSD induced illogic? Let’s just not apply occam’s razor to it because I prefer being superior to you"

What a load of bull (the link). He's basically running the apparent paradox that lead to Michel-Morley's experiment, which itself lead to the need for SR.

Forget about the link and its argument.
Can you pls. explain in plain english the Dopppler effect for light ?
 
  • #4
The frequency of light is simply the energy of it. (IE the greater the energy of the photon, the greater its frequency)

If I am running away from light, then when that light hits me, it doesn't impart as much energy into me since I'm already moving, hence it will be redshifted. And its the opposite case for me heading towards light.

The photon itself is merely an electromagnetic wave that doesn't require a physical substance to vibrate in, not air, not water, nothing. The wave itself is vibrating. Think of a magnet. It doesn't require a medium to transfer its force. It works equally as well in a vacuum as it does in air.

Also, in regards to the frame of reference stuff, all i can say is how i think of it: Light is already traveling at c. It always travels at c. If your lamp is moving away from you, then because light has to travel at c, it has to "expend" energy to move at c in your direction, hence redshifting it. If the lamp is moving towards you, it gets a "boost" of energy from the velocity of the lamp, blueshifting it. Instead of actually moving faster or slower, the light takes the energy of the observer and the emitter and adds it into itself when it "enters your frame of reference".

Forgive me, I am sure I've broken a dozen rules on science, light, and relativity, but that's kind of how i picture it.
 
  • #5
fsoica, the link is not appropriate for this forum at all and should be removed. This forum is not a spot for advertising for fringe and crank websites.

Regarding the Doppler effect. It is very easy. Simply write the equation for the wave as a function of time and position and the equation for the observer's position as a function of time. Then it is just a matter of substitution to find the observed frequency.
 
  • #6
Drakkith explained it very nicely.
 
  • #7
DaleSpam said:
fsoica, the link is not appropriate for this forum at all and should be removed. This forum is not a spot for advertising for fringe and crank websites.

Is there something wrong with posting a link to a website that causes you to question something in science? It seems obvious to me that this isn't a deliberate attempt to advertise the site or anything.
 
  • #8
I have not intended even for a second to advertise anything. I posted that particular link only because after a few hours of searching on the web some text trying to shed some light on the Doppler effect for ... light (for the layman, the one who has no idea of equations and so on), the only site I came up with was that particular alternative theory website.
 
  • #9
Another approach would be to note that the speed of light is constant regardless of the frame of reference, and that frequency and wavelength are constant relative to a specific light source. If a light source and observer are moving towards each other, then the distance between light source and observer decreases with each cycle of a wave, resulting in observed shorter wavelength and higher frequency. If the light source and observer are moving away from each other, the result is an observed longer wavelength and lower frequency.

Wiki has an article that also takes special relativity into account:

http://en.wikipedia.org/wiki/Relativistic_Doppler_effect
 
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  • #10
Drakkith said:
Is there something wrong with posting a link to a website that causes you to question something in science?

The classic lament of the crackpot: "Censorship! I'm being supressed! Science doesn't tolerate dissent!"

Science is built around questioning stuff and dissenting. But we don't have to tolerate crackpots, because they aren't actually interested in our answers to their questions. They're interested in self-aggrandizement and their own Great Theory of Everything. They refuse to learn, no matter how many times you attempt to correct them. They refuse to learn, refuse to admit they might be wrong (or even that they might not know what they think they know), and they just repeat their worn-in misconceptions and crazy ideas over and over like a broken record. That's not skeptical scrutiny and free inquiry, that's the very epitome of closed-mindedness.

So yes. There's something wrong with posting links to obvious crackpot sites: It's explicitly prohibited in the forum rules. And that's an obvious crackpot site. A ridiculously obvious, very stereotypical one, even. There's a reason "Einstein was wrong" has its own http://www.crank.net/einstein.html" [Broken] on crank.net.
 
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  • #11
rcgldr said:
Another approach would be to note that the speed of light is constant regardless of the frame of reference, and that frequency and wavelength are constant relative to a specific light source. If a light source and observer are moving towards each other, then the distance between light source and observer decreases with each cycle of a wave, resulting in observed shorter wavelength and higher frequency. If the light source and observer are moving away from each other, the result is an observed longer wavelength and lower frequency.

Wiki has an article that also takes special relativity into account:

http://en.wikipedia.org/wiki/Relativistic_Doppler_effect

tks. for your reply.
I don't even think of hoping tounderstand the relativistic Doppler effect, since relativity is not one of my forte's.
The relativistic approach only "tweaks" the classical one, the one I have trouble grasping.
If light speed is a constant regardless the reference frame, I understand the energy of a photon and so, its frequency, is not. This is, I think, the difficulty for the non-scientist, to understand the photon as a relative entity, to grasp the reality of a light photon, a quanta, being a variable quantity. How come a "green" photon in a reference frame could become red in another one ?

Assuming one understands relativity, it's ok. It's acceptable (I'm guessing here, of course).

But what becomes of the classical effect ? How could I explain this one in layman's terms ?
 
  • #12
alxm said:
So yes. There's something wrong with posting links to obvious crackpot sites: It's explicitly prohibited in the forum rules. And that's an obvious crackpot site. A ridiculously obvious, very stereotypical one, even. There's a reason "Einstein was wrong" has its own http://www.crank.net/einstein.html" [Broken] on crank.net.

mate, I understand, I made a mistake, but only with good intentions and only because of my limited knowledge, not allowing me to distinguish crap from real potential. But pls. bear with my curiosity and try to shed some light for me regarding my question...
 
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  • #13
Drakkith said:
The frequency of light is simply the energy of it. (IE the greater the energy of the photon, the greater its frequency)

If I am running away from light, then when that light hits me, it doesn't impart as much energy into me since I'm already moving, hence it will be redshifted. And its the opposite case for me heading towards light.

The photon itself is merely an electromagnetic wave that doesn't require a physical substance to vibrate in, not air, not water, nothing. The wave itself is vibrating. Think of a magnet. It doesn't require a medium to transfer its force. It works equally as well in a vacuum as it does in air.

Also, in regards to the frame of reference stuff, all i can say is how i think of it: Light is already traveling at c. It always travels at c. If your lamp is moving away from you, then because light has to travel at c, it has to "expend" energy to move at c in your direction, hence redshifting it. If the lamp is moving towards you, it gets a "boost" of energy from the velocity of the lamp, blueshifting it. Instead of actually moving faster or slower, the light takes the energy of the observer and the emitter and adds it into itself when it "enters your frame of reference".

Forgive me, I am sure I've broken a dozen rules on science, light, and relativity, but that's kind of how i picture it.

tks. for your reply.
nice insights...
 
  • #14
fsoica said:
bear with my curiosity and try to shed some light for me regarding my question...
If you have taken algebra you should be able to do the process I outlined above. Give it a try and let us know, we will be glad to help if you get stuck.
 
  • #15
fsoica said:
But what becomes of the classical effect ? How could I explain this one in layman's terms ?
It's similar to the dopper effect with sound, which I tried to describe in my previous post. If light source and observer are approaching each other, then the start of each wave cycle from the light source occurs increasingly closer to the observer over time, resulting in an observed shorter wavelength and higher frequency. If the source and observer are moving away from each other, then there is an observed longer wavelength and lower frequency. At relatively low speeds compared to c, the relativistic effect is minimal and the effect is similar to that of sound waves. Link to "classic" wiki articles:

http://en.wikipedia.org/wiki/Blue_shift

http://en.wikipedia.org/wiki/Redshift
 
  • #16
Sorry to necro this old thread, but I've been wondering the same thing. I understand the regular doppler effect so don't go on about that. My problem is with regards to light doppler shift.
According to relativity, light's speed is always c in every inertial reference frame, so how is it possible that it imparts less or more energy because of realative motion?
This is particulary difficult when bring particle nature into account.
 
  • #17
In both non-relativistic and relativistic physics, an object's energy and momentum depend on the reference frame (relative velocity) of the observer. If you think of light as a stream of particles with momentum p and energy E = pc, the Doppler effect for light follows from the frame-dependence of energy and momentum (via the Lorentz transformation), together with E = hf.
 
  • #18
So in effect more energy is transferred via photons in objects moving closer relative to each other, one being the source and the other the observer. Its logical, but is there a way to imagine it? Since p is the only variable and E is dependent on p. How does p increase in regards to the actual reference frames? Sorry if I am reasoning in circles but I am having trouble visualising it when c should stay constant.
 
  • #19
If one observer measures an object's momentum and energy as p and E, then another observer who is moving with velocity v with respect to the first observer measures the energy and momentum as

[tex]p^\prime = \gamma \left( p - \frac{vE}{c^2} \right)[/tex]

[tex]E^\prime = \gamma (E - vp)[/tex]

where [itex]\gamma = \frac{1}{\sqrt{1 - v^2/c^2}}[/itex]

This is the Lorentz transformation for momentum and energy, similar to the L.t. for position and time which you may have seen if you've studied relativity.

For a photon, these two equations are equivalent, as you can see by substituting E = pc and E' = p'c.
 
  • #20
Aaah I see. Its what I thought but just didnt have a basis to explain it on. Thanks a lot! :)
 
  • #21
Drakkith said:
Is there something wrong with posting a link to a website that causes you to question something in science? It seems obvious to me that this isn't a deliberate attempt to advertise the site or anything.

Yes that is not allowed, as any link has an effect on such things Google ranking. Thus I also once got a warning (and this explanation) when I referred to a site that the administrators don't want linked.
 
  • #22
fsoica said:
tks. for your reply.
I don't even think of hoping tounderstand the relativistic Doppler effect, since relativity is not one of my forte's.
The relativistic approach only "tweaks" the classical one, the one I have trouble grasping.
If light speed is a constant regardless the reference frame, I understand the energy of a photon and so, its frequency, is not. This is, I think, the difficulty for the non-scientist, to understand the photon as a relative entity, to grasp the reality of a light photon, a quanta, being a variable quantity. How come a "green" photon in a reference frame could become red in another one ?

Assuming one understands relativity, it's ok. It's acceptable (I'm guessing here, of course).

But what becomes of the classical effect ? How could I explain this one in layman's terms ?
You are perfectly right: as you say, the relativistic approach only "tweaks" the classical one. The successful classical model on which relativity is based is that of light as a vibration of an invisible medium, and the classical Doppler effect as well as the relativistic corrections rely on that model of "light waves", similar to sound waves. Classically the Doppler equations for sound and light are identical. With that model, perhaps the best way to view a photon is as a kind of wave packet: a wave pulse of limited dimensions. That doesn't change the Doppler effect.

In laymen's terms, just as with the sound of the horn of a train passing by, also the colour of the light that you receive is affected by the velocity of the source as well as by your own velocity. And the tweaks of relativity make that it is always as if there is a light medium that is in rest with respect to the reference frame that you use; only the relative velocity matters for the Doppler calculation.
 
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  • #23
murdakah said:
Sorry to necro this old thread, but I've been wondering the same thing. I understand the regular doppler effect so don't go on about that. My problem is with regards to light doppler shift.
According to relativity, light's speed is always c in every inertial reference frame, so how is it possible that it imparts less or more energy because of realative motion?
This is particulary difficult when bring particle nature into account.

If you understand the regular doppler effect, then you can apply that knowledge to the relativistic doppler effect as experienced by anyone particular inertial observer. Within that observer's frame of reference, light waves are analogous to sound waves in air provided there is no wind! Anything you can conclude about the change in frequency and wavelength of a moving source of sound has its equivalent for light waves. Einstein's great insight was that any other observers moving at constant speed relative to the first will also find themselves "at rest in the medium".

Edit: I should mention that the analogy applies to frequency and wavelength. The energy of the light photons is the frequency times Plank's constant. Why so, is a question to be answered elsewhere.
 
  • #24
harrylin said:
Yes that is not allowed, as any link has an effect on such things Google ranking. Thus I also once got a warning (and this explanation) when I referred to a site that the administrators don't want linked.

Whoa! I made that post way back when I was but a fresh faced PFer new to the site. Now I am a grizzled old PFer with 5k+ posts under my belt and understand the rules much better. But you are correct in your post, such sites are not allowed to be linked here on PF.
 

1. What is the Doppler effect for light?

The Doppler effect for light is the change in frequency or wavelength of a light wave as observed by an observer due to the relative motion between the source of the light and the observer. This effect is similar to the change in pitch of a sound wave as a moving object passes by.

2. How does the Doppler effect for light work?

The Doppler effect for light is based on the principle that the wavelength of a light wave changes when the source of the light or the observer is in motion. If the source of light is moving towards the observer, the wavelength appears shorter and the frequency appears higher. If the source of light is moving away from the observer, the wavelength appears longer and the frequency appears lower.

3. What causes the Doppler effect for light?

The Doppler effect for light is caused by the relative motion between the source of light and the observer. This can be observed in scenarios such as a moving car with its headlights on or a star moving towards or away from the Earth.

4. How is the Doppler effect for light different from the Doppler effect for sound?

The main difference between the Doppler effect for light and sound is the medium through which they travel. Sound waves travel through a medium such as air, while light waves can travel through a vacuum. Additionally, the Doppler effect for light involves a change in wavelength, while the Doppler effect for sound involves a change in pitch.

5. What are some practical applications of the Doppler effect for light?

The Doppler effect for light has many practical applications in various fields such as astronomy, meteorology, and traffic safety. It is used to measure the speed and distance of celestial objects, predict weather patterns, and detect the speed of moving objects such as vehicles. It is also used in medical imaging techniques like ultrasound.

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