- #1
Imperil
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Hi! I am new here and can't for the life of me figure out what I am doing wrong solving this problem, if someone could help that would be great!
QUESTION:
A bird takes 8.5 s to fly from position A (va= 4.4 m/s (31 ° S of E) to position B(vb= 7.8 m/s ( 25° N of E) along the path. Find the bird's average acceleration.
MY ANSWER
vax/va = cos31
vax = 3.8 m/s
vay/va = sin31
vay = -2.3 m/s
vbx/vb = cos25
vbx = 7.1 m/s
vby/vb = sin32
vby = 3.3 m/s
ax = vbx - vax / t
ax = 7.1 m/s - 3.8 m/s / 8.5s
ax = 0.4 m/s(2)
ay = vby - vbx / t
ay = 3.3 m/s + 2.3 m/s / 8.5s
ay = 0.7 m/s(2)
a(2) = ax(2) + ay(2)
a(2) = 0.16 + 0.49
a = 0.8 m/s(2)
tan(theta) = ay / ax
tan(theta) = 0.7 m/s(2) / 0.4 m/s(2)
tan(theta) = 1.75
theta = 60 degrees
Therefore the bird's acerage acceleration is 0.8 m/s 60 degrees N of E.
QUESTION:
A bird takes 8.5 s to fly from position A (va= 4.4 m/s (31 ° S of E) to position B(vb= 7.8 m/s ( 25° N of E) along the path. Find the bird's average acceleration.
MY ANSWER
vax/va = cos31
vax = 3.8 m/s
vay/va = sin31
vay = -2.3 m/s
vbx/vb = cos25
vbx = 7.1 m/s
vby/vb = sin32
vby = 3.3 m/s
ax = vbx - vax / t
ax = 7.1 m/s - 3.8 m/s / 8.5s
ax = 0.4 m/s(2)
ay = vby - vbx / t
ay = 3.3 m/s + 2.3 m/s / 8.5s
ay = 0.7 m/s(2)
a(2) = ax(2) + ay(2)
a(2) = 0.16 + 0.49
a = 0.8 m/s(2)
tan(theta) = ay / ax
tan(theta) = 0.7 m/s(2) / 0.4 m/s(2)
tan(theta) = 1.75
theta = 60 degrees
Therefore the bird's acerage acceleration is 0.8 m/s 60 degrees N of E.