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scholio
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Homework Statement
a 0.2 meter straight piece of wire has a current of 30 ampere flowing through it, pointing in the +z direction. the magnetic field presented in space is given by:
B = 2B_0i + 4B_0j + 3B_0k
what is the force on the wire?
Homework Equations
magnetic force on a current F = IL X B = ILBsin(theta)where X indicate cross product, I is current, L is length, B is magnetic field
The Attempt at a Solution
F = IL X B
F = ILB sin(theta)
F = (30)(0.2)(2B_0i + 4B_0j + 3B_0k) sin(90)
F = 12B_0i + 24B_0j + 18B_0k
i'm not sure sure whether i did the calculation correct, is the 30 amps only multiplied with the 3B_0k since the current points in the +z direction? i multiplied it through all, i,j,k.
will my final answer be presented in components of each axis?