Wave collapse vs. Friis transmission equation

In summary: If you take the limit as R approaches zero, the Friis equation has the power received going to infinity for any transmitted power - which implies that there is some minimum radius at which the formula can be applied.Conversely, I don't know of any maximum radius at which wave collapse might occur, but it does not appear valid to assume that any such radius would be in the range where the Friis transmission equation can be applied.
  • #1
Antenna Guy
303
0
If waves collapse upon detection, how is it that the Friis transmission equation yields accurate results?

Regards,

Bill
 
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  • #2
Antenna Guy said:
If waves collapse upon detection, how is it that the Friis transmission equation yields accurate results?

Regards,

Bill

Hi Bill

I'm going to quote from Wikipedia here:

"The ideal conditions are almost never achieved in ordinary terrestrial communications, due to obstructions, reflections from buildings, and most importantly reflections from the ground. One situation where the equation is reasonably accurate is in satellite communications when there is negligible atmospheric absorption; another situation is in anechoic chambers specifically designed to minimize reflections."

I just want to point out that Wikipedia says you can use this formula in outer space or in anechoic chambers. It says nothing about applying it at the atomic level. In fact, you can find all kinds of references where they use the cross sectional area of the atom when calculating things like the photoelectric effect.
 
  • #3
Thanks for the reply Marty.

Marty said:
I'm going to quote from Wikipedia here:

"The ideal conditions are almost never achieved in ordinary terrestrial communications, due to obstructions, reflections from buildings, and most importantly reflections from the ground. One situation where the equation is reasonably accurate is in satellite communications when there is negligible atmospheric absorption; another situation is in anechoic chambers specifically designed to minimize reflections."

The common theme in the above is multipath (or, in the case of obstructions, no/limited direct path between apertures). Other non-ideal conditions involve losses, but these can be accounted for. The Friis transmission equation has been used in a number of less-than-ideal situations with reasonable results.

The crux of the question was to determine if the notion of wave collapse is consistent (on a macroscopic scale) with how spherical waves propogate. In my experience, reception in one direction has no impact on gain in other directions (at least not until diffraction effects begin to fill in the shadow at somewhat larger R). If a spherical wave were to collapse when received, I would expect gain in all directions about the source to be affected by the missing component of the radiated wave spectrum.

Basically, the Friis transmission equation suggests to me that the receive antenna can only capture a fraction of the wave energy that is available - not all of it. For example: in the case of two ideal isotropic radiators, the gains can be replaced with unity, and the formula reduces to the path loss (aka "spreading factor"). Thus, the Friis transmission equation appears to contradict the hypothesis of wave collapse (wherein the energy is either received in total, or it isn't).

Regards,

Bill
 
  • #4
In the interest of provoking some conversation on this topic, I'd like to expand upon what "gain" in the Friis transmission equation is.

An antenna's gain is comprised of two parts:

1) Directivity
2) Losses

Losses apply equally in all directions, and directivity relates the radiated power density in a particular direction to that of an isotropic source radiating the same power. Because of reciprocity, the relative strength of a signal received from from a particular direction is directly related to the antenna's ability to radiate a signal of the same frequency in the same direction.

For all intents and purposes, the directivity of an antenna must be related to the probability that a particular photon will be observed in a given direction relative to the source.

Returning to the original question: How is it that what supposedly must hold at infinitesimal scale does not hold at macroscopic scale?

Regards,

Bill
 
  • #5
Antenna Guy said:
Returning to the original question: How is it that what supposedly must hold at infinitesimal scale does not hold at macroscopic scale?

Don't you mean it the other way around? The Friis equation applies at the macroscopic scale but not when applied the capture of single photons?
 
  • #6
Marty said:
Don't you mean it the other way around? The Friis equation applies at the macroscopic scale but not when applied the capture of single photons?

If you take the limit as R approaches zero, the Friis equation has the power received going to infinity for any transmitted power - which implies that there is some minimum radius at which the formula can be applied.

Conversely, I don't know of any maximum radius at which wave collapse might occur, but it does not appear valid to assume that any such radius would be in the range where the Friis transmission equation can be applied.

Regards,

Bill
 

1. What is wave collapse in terms of the Friis transmission equation?

Wave collapse refers to the phenomenon where the transmitted wavefront spreads out and becomes less intense as it propagates through a medium. In the Friis transmission equation, this is represented by the term 1/(4πd2), where d is the distance between the transmitter and receiver.

2. Is wave collapse accounted for in the Friis transmission equation?

Yes, the Friis transmission equation takes into account wave collapse by including the 1/(4πd2) term, which represents the decrease in signal strength due to the spreading of the wavefront. This term becomes more significant as the distance between the transmitter and receiver increases.

3. How does the Friis transmission equation differ from other transmission equations?

The Friis transmission equation is specifically designed for free space propagation, meaning that there are no obstacles or reflections to interfere with the signal. Other transmission equations may account for obstacles or reflections by including additional terms or parameters.

4. Can the Friis transmission equation be used for all types of waves?

No, the Friis transmission equation is most commonly used for electromagnetic waves, such as radio waves and light waves. It can also be used for other types of waves, such as sound waves, as long as the medium is free space and there is no interference.

5. How accurate is the Friis transmission equation?

The Friis transmission equation is a simplified model and may not accurately represent real-life scenarios. It assumes a perfect line-of-sight between the transmitter and receiver and does not account for obstacles or reflections. However, in free space conditions, it can provide a good estimate of signal strength and is commonly used in wireless communication systems.

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