- #1
SteliosVas
- 70
- 0
Given: cos(x)[itex]\frac{1}{x}[/itex]
Find [itex]\frac{dy}{dx}[/itex]:
Now I know... [itex]\frac{dy}{dx}[/itex] of cos(x) = -sin(x)
and [itex]\frac{dy}{dx}[/itex] of [itex]\frac{1}{x}[/itex]= [itex]\frac{-1}{x^2}[/itex]
But I am unsure what formula to apply, and where to go from here?
Find [itex]\frac{dy}{dx}[/itex]:
Now I know... [itex]\frac{dy}{dx}[/itex] of cos(x) = -sin(x)
and [itex]\frac{dy}{dx}[/itex] of [itex]\frac{1}{x}[/itex]= [itex]\frac{-1}{x^2}[/itex]
But I am unsure what formula to apply, and where to go from here?