- #1
uperkurk
- 167
- 0
I'm probably making a silly mistake or Wolfram Alpha is lying to me.
Question: Find the value of c and d.
[itex]3d=13-2c[/itex]
[itex]\frac{3c+d}{2}=8[/itex]
Rearranged, simplified and multiply each equation by 2:
[tex]6d+4c=26[/tex]
[tex]d+3c=16[/tex]
Now find the common multiple which in my case I will use 12:
[tex]18d+12c=78[/tex]
[tex]-4d-12c=-64[/tex]
Then add them and find what d is worth:
[tex]14d=14[/tex]
[tex]d=1[/tex]
Now when I plug this back into the equation, I will use the first one:
[tex]3(1)+2c=13[/tex]
[tex]3+2(c)=13[/tex]
[tex]c=5[/tex]
[tex]d=1, c=5[/tex]
What am I doing wrong? Sorry if this is the long winded way to do it.
Question: Find the value of c and d.
[itex]3d=13-2c[/itex]
[itex]\frac{3c+d}{2}=8[/itex]
Rearranged, simplified and multiply each equation by 2:
[tex]6d+4c=26[/tex]
[tex]d+3c=16[/tex]
Now find the common multiple which in my case I will use 12:
[tex]18d+12c=78[/tex]
[tex]-4d-12c=-64[/tex]
Then add them and find what d is worth:
[tex]14d=14[/tex]
[tex]d=1[/tex]
Now when I plug this back into the equation, I will use the first one:
[tex]3(1)+2c=13[/tex]
[tex]3+2(c)=13[/tex]
[tex]c=5[/tex]
[tex]d=1, c=5[/tex]
What am I doing wrong? Sorry if this is the long winded way to do it.