- #1
sauri
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I got this algebra problem that I have been trying to get around but the answer I get is always different from the book.
It says: Find all the real solutions, if any of each equation.
21). [tex]\sqrt{2x-3} +x=3[/tex].
I tried to resolve it using the following method:
2x-3+x^2=9
(2x-12)+(x^2-9)=0
2(x-6)+(x+3)(x-3)=0
(x+3) and (x-3) will cancel each other so;
2x-12=0
x=12/2
x=6.
However, this is wrong and I know it, cause the answer does not fit the equation. So can anyone help me point what's wrong with what I did?
It says: Find all the real solutions, if any of each equation.
21). [tex]\sqrt{2x-3} +x=3[/tex].
I tried to resolve it using the following method:
2x-3+x^2=9
(2x-12)+(x^2-9)=0
2(x-6)+(x+3)(x-3)=0
(x+3) and (x-3) will cancel each other so;
2x-12=0
x=12/2
x=6.
However, this is wrong and I know it, cause the answer does not fit the equation. So can anyone help me point what's wrong with what I did?