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jameson2
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Homework Statement
Find the differential cross-section for small-angle scattering in a field
U(r)=a/sqrt(b^2 + r^2)
Homework Equations
(let p be the greek letter ro, s be sigma, t be theeta)
the general formula for small angle scattering is:
Equation 1: ds=absolute value(dp/dt)*(p(t)/t)*do where do is the solid angle.
To be able to use this formula, need p(t), which comes from the formula:
Equation 2: t=-(2p/mv^2)*(integrate from p to infinity) (dU/dr)(dr/sqrt(r^2 - p^2))
where v is the velocity at infinity.
The Attempt at a Solution
Using equation 2, by substituting in for dU/dr, I get:
t= -(2p/mv^2)*(int from p to infinity) (-0.5*2ra/(b^2 +r^2)^(3/2))(dr/sqrt(r^2 - p^2))
tidying up a bit:
t= (2pa/mv^2)*(int from p to infinity) [r*dr]/[((b^2 +r^2)^(3/2))(sqrt(r^2 - p^2))]
I think I'm right so far, but I'm stumped here when it comes to evaluating the integral. I basically don't know what substitution to use.