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mahela007
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Can you show me how to prove that an object, if thrown up under gravitational force, will take the same time to reach the apex of it's trajectory as it takes to fall back to it's original position? (ignore air resistance)
mahela007 said:Can you show me how to prove that an object, if thrown up under gravitational force, will take the same time to reach the apex of it's trajectory as it takes to fall back to it's original position? (ignore air resistance)
The equation for calculating the height of an object thrown up under gravity is h = v0t - 1/2gt2, where h is the height, v0 is the initial velocity, g is the acceleration due to gravity (9.8 m/s2), and t is the time.
The mass of an object does not affect its trajectory when thrown up under gravity. All objects, regardless of their mass, will follow the same path and reach the same maximum height when thrown up under gravity.
No, an object thrown up under gravity cannot reach an infinite height. As the object travels upwards, it will experience a downward acceleration due to gravity, eventually causing it to slow down and fall back to the ground.
Air resistance can affect the motion of an object thrown up under gravity. As the object moves upwards, it will experience air resistance, which can slow it down and reduce its maximum height. However, in most cases, the effects of air resistance are negligible and can be ignored.
No, the initial velocity of an object thrown up under gravity cannot be greater than the escape velocity of Earth (11.2 km/s). If the object's initial velocity is greater than the escape velocity, it will escape Earth's gravitational pull and continue moving away from the planet.