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kingwinner
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Partial differential equations represented as "operators"
Partial differential equations (PDEs) can be represented in the form Lu=f(x,y) where L is an operator.
Example:
Input: u(x,y)
Operator: L=∂xy + cos(x) + (∂y)2
=> Output: Lu = uxy+cos(x) u + (uy)2
N/A
I don't understand the parts in red.
What does (∂y)2 mean? Shouldn't it mean (∂y)(∂y) which (I believe) means taking the second partial derivative with respect to y. But the above example seems to imply that (∂y)2 means take the partial derivative with respect to y and then square the result. But I just can't possibly understand how (∂y)2u would be equal to (∂yu)2
I don't have a lot of experience working with operators, so I am feeling really confused. Could someone please kindly explain?
Thank you very much!
Homework Statement
Partial differential equations (PDEs) can be represented in the form Lu=f(x,y) where L is an operator.
Example:
Input: u(x,y)
Operator: L=∂xy + cos(x) + (∂y)2
=> Output: Lu = uxy+cos(x) u + (uy)2
Homework Equations
N/A
The Attempt at a Solution
I don't understand the parts in red.
What does (∂y)2 mean? Shouldn't it mean (∂y)(∂y) which (I believe) means taking the second partial derivative with respect to y. But the above example seems to imply that (∂y)2 means take the partial derivative with respect to y and then square the result. But I just can't possibly understand how (∂y)2u would be equal to (∂yu)2
I don't have a lot of experience working with operators, so I am feeling really confused. Could someone please kindly explain?
Thank you very much!