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irNewton
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Homework Statement
It is supposed to be a glycol with a formula of C6H14O2.
The H NMR integrations are 6H and 1H as indicated on the H NMR.
The IR:
http://imageshack.us/photo/my-images/90/18155707.jpg/
The H NMR:
http://imageshack.us/photo/my-images/155/hnmr.jpg/
Homework Equations
IDH = (2+ (2*#C)- #H)/2
The Attempt at a Solution
I calculated the IDH to be zero meaning that it is a straight chain.
My guess is:
CH3 CH3
| |
OH--C----C--OH
| |
CH3 CH3
I'm not sure if it's right though.| |
OH--C----C--OH
| |
CH3 CH3
Thanks a lot to anyone who helps out!