- #1
gadje
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I'm going over the notes from my thermodynamics course, with the aid of Feynman I (p44-12).
Feynman uses the example of putting a hot stone at temperature [tex]T_1[/tex] into cold water at temperature [tex]T_2[/tex] causing a flow of heat [tex]\Delta Q[/tex] between the two.
The entropy change is given to be [tex]\Delta S = \frac{\Delta Q}{T_2} - \frac{\Delta Q}{T_1}[/tex].
Does this mean that one only needs to take into account the initial temperatures and the total flow of heat from one to the other in order to calculate the change in entropy? I keep thinking that there should be some sort of [tex]\Delta T[/tex] term - why isn't this the case?
Cheers.
Feynman uses the example of putting a hot stone at temperature [tex]T_1[/tex] into cold water at temperature [tex]T_2[/tex] causing a flow of heat [tex]\Delta Q[/tex] between the two.
The entropy change is given to be [tex]\Delta S = \frac{\Delta Q}{T_2} - \frac{\Delta Q}{T_1}[/tex].
Does this mean that one only needs to take into account the initial temperatures and the total flow of heat from one to the other in order to calculate the change in entropy? I keep thinking that there should be some sort of [tex]\Delta T[/tex] term - why isn't this the case?
Cheers.