- #1
fishingspree2
- 139
- 0
Say I have a solid given using polar coordinates
I want to compute its volume.
We know that when switching from cartesian to polar, dV becomes [tex]\rho^{2}\sin\phi d\rho d\theta d\phi[/tex]
But I am not converting from cartesian to polar, I am already in polar coordinates.
do I still have to carry the [tex]\rho^{2}\sin\phi[/tex] that comes from the dV conversion formula?
I want to compute its volume.
We know that when switching from cartesian to polar, dV becomes [tex]\rho^{2}\sin\phi d\rho d\theta d\phi[/tex]
But I am not converting from cartesian to polar, I am already in polar coordinates.
do I still have to carry the [tex]\rho^{2}\sin\phi[/tex] that comes from the dV conversion formula?