Compton Effect (scattered photon angle)

In summary, for the Compton Effect, the equation for tan(ϴ) is given by tan(ϴ) = (sinφ)/[(Δλ/λ') + (1-cosφ)], where ϴ is the angle between the scattered photon and the incident photon, and φ is the angle between the scattered electron and the incident photon. It is important to use the correct equations for photon and electron energy and momentum, and to consider the conservation of energy and momentum in the scattering process.
  • #1
BAlexanderSUS
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Homework Statement



Show that for Compton Effect: tan(ϴ) = (sinφ)/[(Δλ/λ) + (1-cosφ)]

Where,
ϴ = angle that the scattered photon makes with the incident photon
φ = angle that hte scattered electron makes with the incident photon

Homework Equations



For Photon:

initial;
E=hv
p=hv/c
(where v is frequency)

final;
E=hvʹ
p=hvʹ/c

For Electron;

initial;
E=mc^2
p=0

final;
p=p
E=sqrt(m^2c^4+p^2c^2)

note* (changed the v/c to 1/λ)


The Attempt at a Solution



Breaking the problem into components and solving for ϴ such that tanϴ=sinϴ/cosϴ:

X; (h/λ) = (h/λʹ)cosϴ +Pcosφ
Y; 0=(h/λʹ)sinϴ-Psinφ

so,

cosϴ=[((h/λ)-Pcosφ)λʹ]/h
sinϴ=Psinφ(λʹ)/h

tanϴ=sinϴ/cosϴ

so,

tanϴ=Psinφ/((h/λ)-Pcosφ)

from here I am lost, I'm assuming that there must be an property of momentum that I am not taking into account. Any help would be appreciated! thank you!
 
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  • #2






Thank you for your post. I am a scientist and I would like to help you solve this problem. First of all, you have the right idea by breaking the problem into components and using the equations for photon and electron energy and momentum. However, there are a few corrections and additions that need to be made to your attempt at a solution.

1. The equation for the scattered photon's energy should be E = hc/λ', not E = hv'/c. This is because in Compton scattering, the energy of the photon changes due to the interaction with the electron, but the frequency remains the same.

2. The equation for the scattered electron's energy should be E = sqrt(m^2c^4 + p^2c^2), not E = mc^2. This is because the electron's energy also changes due to the interaction with the photon, and its momentum is not zero in the final state.

3. In your attempt at a solution, you have used the same momentum value for the initial and final state of the electron. However, in Compton scattering, the momentum of the electron changes due to the interaction with the photon. The correct equation for the electron's momentum in the final state is p = sqrt((h/λ')^2 + (Pcosφ)^2 - 2(h/λ')(Pcosφ)cosϴ).

4. In the equation for cosϴ, you have used (h/λ) as the momentum value for the initial state of the photon. However, this should be (h/λ') since the photon's momentum changes after the interaction with the electron.

With these corrections and additions, you should be able to obtain the correct expression for tanϴ. Remember to use the fact that the total energy and momentum must be conserved in the scattering process. I hope this helps. Good luck!
 

1. What is the Compton Effect?

The Compton Effect, also known as Compton scattering, is a phenomenon in which a photon (a particle of light) collides with an electron and transfers some of its energy to the electron. This results in a change in the wavelength and direction of the photon.

2. How does the scattered photon's angle relate to the incident photon's angle?

The scattered photon's angle is directly related to the incident photon's angle. As the incident photon's angle increases, the scattered photon's angle also increases. This relationship is described by the Compton scattering equation: θs = θi + θ - 180°, where θs is the scattered photon's angle, θi is the incident photon's angle, and θ is the angle between the incident photon's direction and the direction of the electron after the collision.

3. How does the energy of the scattered photon compare to that of the incident photon?

The energy of the scattered photon is lower than that of the incident photon. This is because the photon loses some of its energy during the collision with the electron. The amount of energy lost is directly related to the angle of scattering and can be calculated using the Compton scattering equation: ΔE = h/mec(1 - cosθ), where ΔE is the change in energy, h is Planck's constant, me is the mass of the electron, and c is the speed of light.

4. What is the significance of the Compton Effect?

The Compton Effect is significant because it provided evidence for the particle-like nature of light and helped to confirm the theory of quantum mechanics. It also has practical applications in various fields such as medical imaging, materials science, and nuclear physics.

5. How is the Compton Effect different from other types of scattering?

The Compton Effect is different from other types of scattering, such as Rayleigh and Thomson scattering, because it involves a change in the energy and direction of the photon. In Rayleigh scattering, the photon's energy remains the same, and in Thomson scattering, the photon's energy is much lower than that of the incident photon. Additionally, the Compton Effect is only significant for high-energy photons, whereas other types of scattering can occur with lower-energy photons.

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