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pacu
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Problem statement:
Two identical cyclists ride past each other with constant velocities Va and Vb, which are close to the speed of light. Can it be that cyclist A perceives cyclist B as shorter or longer that cyclist B perceives cyclist A ? Or simply La is NOT equal to Lb ? (La-length of cyclist A as seen by cyclist B, Lb -length of cyclist B as seen by cyclist A).
Relevant formulas:
Relative speed V = Va+Vb/(1+(Va*Vb/c^2))
Relative length l = lo * square root from 1-(V/c)^2
Conclusion:
The V from the second equation is equal for both cyclists, since addition and multiplication are alternate. lo is also equal. So there is no difference in the way cyclists A and B see each other.
Is this conclusion right?
Two identical cyclists ride past each other with constant velocities Va and Vb, which are close to the speed of light. Can it be that cyclist A perceives cyclist B as shorter or longer that cyclist B perceives cyclist A ? Or simply La is NOT equal to Lb ? (La-length of cyclist A as seen by cyclist B, Lb -length of cyclist B as seen by cyclist A).
Relevant formulas:
Relative speed V = Va+Vb/(1+(Va*Vb/c^2))
Relative length l = lo * square root from 1-(V/c)^2
Conclusion:
The V from the second equation is equal for both cyclists, since addition and multiplication are alternate. lo is also equal. So there is no difference in the way cyclists A and B see each other.
Is this conclusion right?
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