- #1
aisha
- 584
- 0
use you accepted value for the solubility product of lead 2 chloride to determine the solubility of lead 2 chloride in mol/L and g/L
the accepted value is ksp=1.2*10^-5
Ksp=[Pb] [Cl]^2
1.2*10^-5 = (x) (2x)^2
x=0.014 mol/L
0.014 mol/L * 276.1 g/mol
=3.98 g/L
I don't know if I did this right can someone please tell me ASAP
the accepted value is ksp=1.2*10^-5
Ksp=[Pb] [Cl]^2
1.2*10^-5 = (x) (2x)^2
x=0.014 mol/L
0.014 mol/L * 276.1 g/mol
=3.98 g/L
I don't know if I did this right can someone please tell me ASAP