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jagged06
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Homework Statement
How much heat must be removed when 130 g of steam at 145°C is cooled and frozen into 130 g of ice at 0°C. (Take the specific heat of steam to be 2.01 kJ/kg·K.)
Answer is in kcal.
Homework Equations
The Attempt at a Solution
I know steam turns back into water at 100°C
Q1=C1m(deltaT)
Q1=(2010 J//kg·K)(.13kg)(418.15K-373.15K)
In the second part, instead of using the specific heat of steam, I used the specific heat of water= 4.186 joule/gram °C
Q2=C2m(deltaT)
Q2=(4.186 J/g·°C)(130g)(100°C)
I then added Q1 to Q2 and came up with an answer in Joules.
1 joule = 0.000239005736 kilocalories
But my answer is wrong. Anyone see what I missed? Probably a conversion issue.