- #1
vinny380
- 29
- 7
The length of a simple pendulum is .760m, the pendulum bob has a mass of .365 kg, and it is released at at angle 12 degress to the vertical.
A. Find the frequency. Assume SHM.
B. What is the pendulum bob's speed when it passes through the lowest point of the swing
C. What is the tot al energy stored in this oscilation, assuming no loses.
So A is really easy:
F=(1/2pi)sqrt(9.8/.76)
F= .57
For me, B is the hardest part because I can not find a relevant formula connecting velocity with pendulums. Can anyone advise me how to do this part??
C. I haven't worked on this part yet, but I am ready sure you just have to use the formula E= .5mv^2 +.5kx^2.
Thanks!
A. Find the frequency. Assume SHM.
B. What is the pendulum bob's speed when it passes through the lowest point of the swing
C. What is the tot al energy stored in this oscilation, assuming no loses.
So A is really easy:
F=(1/2pi)sqrt(9.8/.76)
F= .57
For me, B is the hardest part because I can not find a relevant formula connecting velocity with pendulums. Can anyone advise me how to do this part??
C. I haven't worked on this part yet, but I am ready sure you just have to use the formula E= .5mv^2 +.5kx^2.
Thanks!