- #1
Ed Quanta
- 297
- 0
So here is an example of what I am trying to do.
We know that div of an E field=p/eo
where p=charge density and eo=the permittivity of free space. This equation is expressed in MKSA units. In order to convert this into Gaussian units, we must multiply E by 1/sqare root of 4*pi*eo, and multiply p by square root of 4*pi*eo.
Thus we are left with E= p*4*pi in Gaussian units
Now where A is a vector field and T is a potential scalar, I know that B=curl of A
and E=-gradient of T -1/c*dA/dt in the Gaussian unitss. I have to then convert this into MKSA. I am not sure what to do here because unlike the example which I dealt with above, I do not know how to convert both sides of the equation accordingly. Help anyone?
We know that div of an E field=p/eo
where p=charge density and eo=the permittivity of free space. This equation is expressed in MKSA units. In order to convert this into Gaussian units, we must multiply E by 1/sqare root of 4*pi*eo, and multiply p by square root of 4*pi*eo.
Thus we are left with E= p*4*pi in Gaussian units
Now where A is a vector field and T is a potential scalar, I know that B=curl of A
and E=-gradient of T -1/c*dA/dt in the Gaussian unitss. I have to then convert this into MKSA. I am not sure what to do here because unlike the example which I dealt with above, I do not know how to convert both sides of the equation accordingly. Help anyone?