- #1
SD43
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Homework Statement
I need to calculate the replacement resistance Rv (Ohm) of the following
R1 = 12 ohm
R2 = 8 ohm
R3 = 6 ohm
R4 = 4 ohm
R5 = 9 ohm
R6 = 12 ohm
R7 = 4 ohm
I've been trying to include a picture that I've drawn in paint but apparently a couple of lines exceeds the 100Kb line. So I'm afraid I'm going to have picture the drawing in your mind.
R1 and R2 are right next to each other so it's alright if you put them together so 12 + 8 makes 20 Ohm
Under R1 and R2 there's R3
Directly under R3 there's R4.
Next to R4 on the right side there's R5
Under R5 there's R6
Between R5 and R6 there's R7 which isn't parallel to them.
I'm sorry for the confusion, but there's just no other way.
My teacher said the answer should be 9,7 ohm with lots of variables behind the 7
Homework Equations
1/Rv = 1/R1 + 1/R2 + 1/R3 + 1/R4 + 1/R5 +1/R6
The Attempt at a Solution
1/20 + 1/6 + 1/4 = 7/ 15
15/7 = 2,14
1/9 + 1/12 = 7/36
36/7 = 5,14
5,14 + 2,14 = 7,28
1/4 = 0,25
0,25 + 7,28 doesn't make 9,7
If you just use the equation 1/Rv = 1/R1 + 1/R2 ... you should get 41/45 which again doesn't make 9,77.
So after 2 days of being puzzled I decided the internet was a good place to find the right way to get to 9,7