- #1
jturn
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Homework Statement
A chain consisting of five links, each of mass 0.105 kg, is lifted vertically with a constant acceleration of a = 3.5 m/s2. Find the magnitude of the force that link 3 exerts on link 2.
Homework Equations
F = ma
The Attempt at a Solution
I did:
F = ma
FU - (0.105 * 3)(9.8) = (0.105) * 3.5
FU = 4.19 N
where FU is the force pulling up, (0.105*3) is the mass of the link's 5, 4, and 3 weighing down on link 2 (mg=weight) and then the mass*accel on the other side.
This is wrong. why? and how do i get the right answer?